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Bandwidth VS Sub-packetization in High-rate MDS Codes for Distributed Storage Systems

Date: 2020-06-04    Hits:    Source:

Speaker: Dr. Jie Li is a postdoc at the Department of Mathematics and System Analysis, Aalto University,  Finland. In June 2017, he received his doctorate from Southwest  Jiaotong University. During his doctorate, he visited the Department of  Electronic Engineering and Computer Science of the University of  Tennessee for one year with the support of CSC. From June 2017 to  February 2019, he did his postdoc at the Mathematics Department of Hubei  University, during which he visited Hong Kong University of Science and  Technology and University of Maryland. His main research directions are  distributed storage system, secret information extraction, distributed  computing, sequence design, cryptography theory and so on. In recent  years, he has published more than 10 SCI papers in journals such as IEEE  Trans. Inf. theory, IEEE Trans. Commun., and presided over the youth  fund project of NSFC and one general support project of China  Postdoctoral fund. Dr. Li was awarded IEEE Jack Keil Wolf ISIT Student  Paper Award in 2017 and IEEE Chengdu Section Excellent Student Paper  Award in 2016.

Date: June 05, 2020

Time: 14:00-15:00

Location: Welcome to ZOOM meeting, https://zoom.com.cn/j/2936654514



Abstract:

Optimal  node repair in coding for distributed storage systems is a central  topic. However, existing high-rate maximum distance separable (MDS)  codes with the optimal repair bandwidth require a significantly large  sub-packetization level, which may prevent the codes to be implemented  in practical systems. In this talk, we first introduce a generic  transformation that can convert any nonbinary MDS code into another one  such that some target nodes can be optimally repaired, and then present  another transformation that can greatly reduce the sub-packetization  level of high-rate MDS codes with the optimal repair bandwidth.


Source: School of Cyber Science and Technology

Edited by: Liu Fang


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